CHECKMATE!         

 

Here are the solutions to the five positions given last week.  All positions lead either to checkmate or force resignation due to a threatened checkmate.

Following are the answers to the questions osed last week.

 

This will be the final article in this series.

27/08/2011 13:13:28

 












(61) Kamishov - Sokolsky
1938
[Bill Frost]

1...Ne2+ 2.Kh1 Qxg4 3.hxg4 [3.Qxd6 Qg5 4.Qb8+ Re8 5.Qxb7 Rxc4 6.Qd7 Qe5 7.Rd5 Qe4 8.Rfd1 Rd4 and Black wins.] 3...Rh5+ 4.gxh5 Rh4# 0-1

(62) Van den Eiden - Prashak
1974
[Bill Frost]

1.Re8 Qd7 [1...Qxe8 2.Rxe8 Ng8 3.Qe2 Kh8 4.Nh5 and White wins.] 2.Qxg5+ fxg5 3.Nh5# 1-0

(63) Chigorin - Schiffers
1878
[Bill Frost]

1.Qxe7+ Rxe7 2.Rxe7+ Rf7 3.Ne6+ Kg8 4.Re8+ Rf8 5.Rxf8# 1-0

(64) Grigoriev - Nadiseva
1973
[Bill Frost]

1...Rxa3+ and wins [1...Rxa3+ 2.Kxa3 Qa1# ; 1...Rxa3+ 2.bxa3 Qa1# ] 0-1

(65) Bartushat - Hirsch
20.08.1935
[Bill Frost]

1...Nxe4 2.Qxd8 Ng3+ 3.Kg1 Nf3# 0-1